Python 3.6 subprocess module returncode with tee command

Question

I am using Python 3.6.9 to call the following bash script:

run_cmds.sh:

ls dir_doesnt_exist | tee log

Here is the Python code:

import subprocess from subprocess import PIPE cmd = subprocess.run(['bash','run_cmds.sh'], stdout=PIPE, stderr=PIPE) print(cmd.stderr.decode()) print("The returned code is:", cmd.returncode)

Running the Python code, I get the following:

ls: cannot access 'dir_doesnt_exist': No such file or directory The returned code is: 0

As you can see, subprocess captures the standard error output but returncode is 0.

What is wrong with my Python script?

I appreciate any help.

adamkgray · Accepted Answer · 2020-01-21 02:35:44Z

The return code IS 0. The return code is the return code of the last command, even when using tee (unless the pipefail variable is set). You can see it for yourself on the command line:

$ ls dir_doesnt_exist | tee log ls: dir_doesnt_exist: No such file or directory $ echo $? 0

However, if you remove the pipe |, you will get a non-zero exit code

$ ls dir_doesnt_exist ls: dir_doesnt_exist: No such file or directory $ echo $? 1

So, when using tee, you have to check the $PIPETSTATUS variable instead of the regular exit code

$ ls dir_doesnt_exist | tee log ls: dir_doesnt_exist: No such file or directory $ echo ${PIPESTATUS[0]} 1

Try making your python code like this

import subprocess from subprocess import PIPE cmd = subprocess.run(['bash','run_cmds.sh; exit ${PIPESTATUS[0]}'], stdout=PIPE, stderr=PIPE) print(cmd.stderr.decode()) print("The returned code is:", cmd.returncode)

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