Input:
'0x0 0x48 0x65 0x6c 0x6c 0x6f 0x8E 0x21' Output:
Hello! Current Solution:
s = [] birary_data = '0x0 0x48 0x65 0x6c 0x6c 0x6f 0x8E 0x21'.replace(' ', '').split('0x') for c in birary_data: if len(c) > 1: s.append(bytes.fromhex(c).decode('utf-8', 'ignore')) print("".join(s)) Need help with:
Could anyone suggest a more elegant solution, please?
Try this:
data = '0x0 0x48 0x65 0x6c 0x6c 0x6f 0x8E 0x21' string = "".join([chr(int(item, 16)) for item in data.split()]) print(string) Output:
Hello! Another option is to remove 3 characters (or less) length substrings, 0x and white spaces. bytes.fromhex can handle a string like '48656c6c6f8E21'
binary_data = '0X0 0x48 0x65 0x6c 0x6c 0x6f 0x8E 0x21' binary_data = re.sub(r'\b\w{3}\b|\s?0x', '', binary_data) print(bytes.fromhex(binary_data).decode('utf-8', 'ignore')) 
r'\b\w{3}\b|\s?0x' to get '48656c6c6f8E21' directly?You can use the below one Here in the code i am first splitting the hex according to white-space and then iterating and joining the character i get.
a = '0x0 0x48 0x65 0x6c 0x6c 0x6f 0x8E 0x21' print(''.join(chr(int(i, 16)) for i in a.split())) The builtin bytes.fromhex() is very nearly all we need. There are however two problems we need to get around:
0x8E)import re data = '0x0 0x48 0x65 0x6c 0x6c 0x6f 0x8E 0x21' string = bytes.fromhex(re.sub('0x(0 )?', '', data)).decode('utf-8', 'ignore') The regex will take care of both stripping the null byte and formatting the string correctly for bytes.fromhex(). The ignore in the decode will skip the bad byte.
birary_data = '0x0 0x48 0x65 0x6c 0x6c 0x6f 0x8E 0x21'.replace('0x', '').split() print(bytearray.fromhex(''.join(c for c in birary_data if len(c) > 1)).decode('utf-8', 'ignore')) Output:
Hello! 