I want to combine four single bytes of data to one datum of four bytes.
#include <stdio.h> #include <stdlib.h> int main(int argc, char *argv[]) { unsigned long int sdata = 0x12*(16^6) + 0x34*(16^4) + 0x56*(16^2) + 0x78; printf("%x %d", sdata, sizeof(sdata)); return 0; } The screen prints:
c20 4 I want to get:
sdata = 0x12345678 The type unsigned long int is a 4 byte data type, so why can't it save the data? Why is the output wrong?
You must use binary operations. More precisely left shifts (<<) and binary or (|).
unsigned int sdata = 0x12<<24 | 0x34<<16 | 0x56<<8 | 0x78; printf("%x %zu\n", sdata, sizeof(sdata)); This yields
12345678 4
unsigned long int is not always 4 bytes, in many implementations it's 8 bytes.
As was said in the comments ^ does not represent power in C, it's a bitwise operator.
Your printf specifiers are not correct, you should use %lx in the first (or %#lx if you'd like to print the 0x prefix) and %zu in the second.
Casting to unsigned long will avoid integer overflow, more so because there are some implementations in which int type is 2 bytes in size.
unsigned long int sdata = (unsigned long int)0x12*16*16*16*16*16*16 + (unsigned long int)0x34*16*16*16*16 + 0x56*(16*16) + 0x78; printf("%#lx %zu", sdata, sizeof(sdata)); Output:
0x12345678 8 //in this demo, as you can see, unsinged long int is 8 bytes Or just use binary operations if you can, as demonstrated by @chmike
