How to send query value without URL encoding in go-lang?

Question

Example:

package main import ( "fmt" "log" "net/url" ) func main() { u, err := url.Parse("http://bing.com/search?q=dotnet") if err != nil { log.Fatal(err) } u.Scheme = "https" u.Host = "google.com" q := u.Query() q.Set("q", "golang../") u.RawQuery = q.Encode() fmt.Println(u) }

Output: https://google.com/search?q=golang..%2F here "/" is encoded to "%2F" what to do if we don't what this and want something like https://google.com/search?q=golang../ I tried to find a lot on google but didn't get anything

%2F didn't work as intended if manually put "/" it works as intended — KATHAN PATEL
– KATHAN PATEL, Commented Sep 13, 2020 at 17:07

KATHAN PATEL · Accepted Answer · 2020-09-13 17:08:33Z

So I Found an Answer to this here the code

package main import ( "fmt" "log" "net/url" ) func main() { u, err := url.Parse("http://bing.com/search?q=dotnet") if err != nil { log.Fatal(err) } u.Scheme = "https" u.Host = "google.com" q := u.Query() q.Set("q", "golang../") u.RawQuery = q.Encode() decoded,err:=url.QueryUnescape(q.Encode()) u.RawQuery= decoded if err != nil { return } fmt.Println(u) }

had to use url.QueryUnescape

Burak Serdar · Accepted Answer · 2020-09-13 17:05:39Z

Set the raw query to what you need, not to the encoded value:

u, err := url.Parse("http://bing.com/search?q=dotnet") if err != nil { log.Fatal(err) } u.Scheme = "https" u.Host = "google.com" u.RawQuery = fmt.Sprintf("q=golang../") fmt.Println(u)

the above code is just an example for the same code I used in my main code and I have undefined params but defined payloads which I need to send as a value in those query params. so this solution is not applicable.

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