How to select first item's sub-value from a nested dictionary? [duplicate]

Question

I have a python dictionary which is described below:

dict={ "Moli": {"Buy": 75, "Sell": 53, "Quantity": 300} "Anna": "Buy": 55, "Sell": 83, "Quantity": 154} "Bob": {"Buy": 25, "Sell": 33, "Quantity": 100} "Annie": {"Buy": 74, "Sell": 83, "Quantity": 96} }

I want to select or print first item's sub-value (i.e: "Buy": 75) of this nested dictionary.

If I am using this code:

print(trading_portfolio[(list(trading_portfolio.keys())[0])]["Buy"])

I'm getting error like this:

select first item from this nested dictionary builtins.KeyError: "Buy"

Welcome to SO! Your code works fine for me but next(iter(d.values()))["Buy"] seems preferable. Never name a variable "dict"--it overwrites a builtin. — ggorlen
– ggorlen, Commented Oct 20, 2020 at 3:47

RajezPrince · Accepted Answer · 2020-10-20 04:44:45Z

you can try this code and if it not meet your expectation please ping me your exact query....

trading_portfolio={ "Moli": {"Buy": 75, "Sell": 53, "Quantity": 300}, "Anna": {"Buy": 55, "Sell": 83, "Quantity": 154}, "Bob": {"Buy": 25, "Sell": 33, "Quantity": 100}, "Annie": {"Buy": 74, "Sell": 83, "Quantity": 96} } print(trading_portfolio[(list(trading_portfolio.keys())[0])]["Buy"])

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