mydat <- structure(list(A = list(0.0513386405422815, 0.0498556819169294), B = list(0.101635583229926, 0.108375425286815), C = list(0.0505800651643873, 0.0491970061885759), D = list(0.100497645341106, 0.107056699263229)), row.names = 1:2, class = "data.frame") > mydat$A [[1]] [1] 0.05133864 [[2]] [1] 0.04985568 mydat is a data.frame, but its columns are all in list format. Is there a quick way to convert these to vectors instead?
You can try
> out <- list2DF(Map(unlist, mydat)) > str(out) 'data.frame': 2 obs. of 4 variables: $ A: num 0.0513 0.0499 $ B: num 0.102 0.108 $ C: num 0.0506 0.0492 $ D: num 0.1 0.107 You can unnest all the columns in the dataframe.
library(tidyr) mydat %>% unnest(cols = everything()) # A B C D # <dbl> <dbl> <dbl> <dbl> #1 0.0513 0.102 0.0506 0.100 #2 0.0499 0.108 0.0492 0.107 Just 'unlist()' them.
lapply(mydat, unlist) $A [1] 0.05133864 0.04985568 $B [1] 0.1016356 0.1083754 $C [1] 0.05058007 0.04919701 $D [1] 0.1004976 0.1070567 In the same vein as apply()-ing unlist, apply()-ing simplify2array:
# Simplify each list to a vector: data.frame(apply(mydat, 2, simplify2array)) 