I'm working on a program in c# where I'm supposed to tell the user to insert random characters and then divide those random characters into letters and numbers and count how many i have of each.
anyone has any idea how to do so? thanks! ps: i'm new to c# and programming alltogether :)
You could use char.IsDigit or char.IsNumber to check if it's a "number"(digit):
string input = Console.ReadLine(); int digitCount = input.Count(char.IsDigit); int letterCount = input.Length - digitCount; You need to add using System.Linq to be able to use Enumerable.Count.
Since you now have asked for counting vowels. Vowels are a, e, i, o, u and their uppercase version. So you could use this method:
private static readonly HashSet<char> Vowels = new HashSet<char> { 'a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U' }; public static bool IsVowel(char c) => Vowels.Contains(c); and this code to count the vowels:
int vowelCount = input.Count(IsVowel); If you don't just want to count them but show them to the user:
string vowelsInInput = new String(input.Where(IsVowel).ToArray()); string noVowels = new String(input.Where(c => !IsVowel(c)).ToArray()); which also gives you the count(for example vowelsInInput.Length).
Get the input and loop through every character within the string
string testStr = "abc123"; foreach (char c in testStr) { Console.WriteLine(c.ToString( )); } 
You can use a dictionary to count the number of times a letter appears.
char letter = //your letter; var charFrequencies = new Dictionary<char, int>(); if (!charFrequencies.ContainsKey(letter)) { charFrequencies.Add(letter, 1); } else { charFrequencies[letter]++; } 