Passing function as a parameter

Question

I want to search an array of NSDate, so here what I do:

searchResult = CFArrayBSearchValues((CFArrayRef)someDateArray, arrayRange, dateToFind, CFDateCompare, nil);

However, I get this warning:

Incompatible pointer types passing 'CFComparisonResult (CFDateRef, CFDateRef, void )' to parameter of type 'CFComparatorFunction' (aka 'CFComparisonResult ()(const void *, const void *, void *)')

How do I properly pass a function as a parameter? I think I got my syntax wrong.

ughoavgfhw · Accepted Answer · 2011-07-22 20:50:58Z

You need to cast the function pointer to the CFComparatorFunction type, since it has a more explicit signature (it uses CFDateRef instead of void *).

searchResult = CFArrayBSearchValues((CFArrayRef)someDateArray, arrayRange, dateToFind, (CFComparatorFunction)CFDateCompare, nil);

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