Return to Revisions

No, an array-type is implicitly converted into pointer type when you pass it in to a function.

So,

void PrintSize(int p_someArray[10]){ printf("%d\n", sizeof(p_someArray)); } 

and

void PrintSize(int *p_someArray){ printf("%d\n", sizeof(p_someArray)); } 

are equivalent. So what you get is the value of sizeof(int*)