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- The current will want to flow through D1 to the 5V rail? What? The voltage to be sampled needs to be between 0 and VCC (5V). If it's lower than 5V, won't D1 be reverse-biased and the potential will be applied to the ADC (which is a capacitor, if I remember correctly)Duncan C– Duncan C2020-06-23 17:38:57 +00:00Commented Jun 23, 2020 at 17:38
- I thought that as long as you stayed within your voltage limits, the ADC was a capacitive input?Duncan C– Duncan C2020-06-23 17:39:36 +00:00Commented Jun 23, 2020 at 17:39
- Oh, I see. I read the OPs question more carefully. He's looking to avoid destroying the input if the ground side of his voltage divider is left open and he pumps 12V into the pin. Yeah, wouldn't a 5V zener diode we the way to go?Duncan C– Duncan C2020-06-23 17:42:10 +00:00Commented Jun 23, 2020 at 17:42
- @DuncanC Belt and braces. Keep the current < 1mA and add the zener. If one fails the other protects.Majenko– Majenko2020-06-23 20:01:26 +00:00Commented Jun 23, 2020 at 20:01
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