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  • \$\begingroup\$ According to my tests, the optimal choice from 0123456789+-*.% for octave is 139-%, which produces an array of 18: 1 2 3 4 6 8 9 13 16 19 22 31 38 39 88 91 92 93. So you can gain another 3 numbers :) \$\endgroup\$ Commented Dec 9, 2016 at 15:48
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    \$\begingroup\$ very crude brute-force that I used to get the 18-number solution: pastebin.com/umckG0VS \$\endgroup\$ Commented Dec 9, 2016 at 15:55
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    \$\begingroup\$ I found that solution too, but that was after seeing the python submission and it's essentially the same thing. Nice job bothering to make a brute force script. 😊 \$\endgroup\$ Commented Dec 9, 2016 at 16:35