Timeline for Sever-sort an array

8 events

when toggle format	what		by	license	comment
Dec 22, 2016 at 4:50	comment	added	ETHproductions		And since `z` is the second parameter in the function, when `f(a,q)` is called, `f` sees it as `z`. Hope this helps!
Dec 22, 2016 at 4:49	comment	added	ETHproductions		@obarakon Well, `f=([n])=>...` would only capture the first element, and `f=([n,a])=>...` would capture only the first in `n` and the second in `a`. Another way to do what `f=([n,...a])=>,,,` does would be `f=a=>(n=a.unshift(),...`.
Dec 22, 2016 at 0:21	comment	added	Oliver		Thank you. That was very helpful. Since your first parameter is an array, why do you need to include the `...a`? Is that just so you can take advantage of `n`? One more thing, when you call `f(a,q)`, does `q` get set to the parameter `z`?
Dec 22, 2016 at 0:12	comment	added	ETHproductions		@obarakon Correct. `n` is the first item in the array, and `a` is the rest of the array. You can find more info here.
Dec 22, 2016 at 0:05	comment	added	Oliver		Can you explain how your array gets parsed into your first parameter `[n,...a]`. What is `n`? Is that just the first item in your array?
Dec 21, 2016 at 23:41	history	edited	ETHproductions	CC BY-SA 3.0	added explanation
Dec 21, 2016 at 23:14	history	edited	ETHproductions	CC BY-SA 3.0	added snippet
Dec 21, 2016 at 22:59	history	answered	ETHproductions	CC BY-SA 3.0