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\$\begingroup\$ I never programmed in Visual Basic, but it seems you can remove the space at If Not p.Contains(j)Then same like you did at If j.Contains(c)Then g=0 below. Also, If Not p.Contains(j)Then \n g=1 \n For Each c In i.ToString \n If j.Contains(c)Then g=0 \n Next \n If g Then Exit While \n End If can be shortened by removing g and using Exit While directly in the for-loop: If Not p.Contains(j)Then \n For Each c In i.ToString \n If j.Contains(c)Then Exit While \n Next \n End If, which will become 241 bytes by the looks of it. \$\endgroup\$

Kevin Cruijssen
– Kevin Cruijssen

2017-11-09 18:20:37 +00:00
Commented Nov 9, 2017 at 18:20
\$\begingroup\$ @KevinCruijssen Definitely can remove the space to make it Contains(c)Then, I just missed it. I like what you're thinking, but I'm using g as a sentinel to see if the string contains the number or not. Your link gives the wrong answers, but I'll see if I can rework some of the inner logic along what you're thinking. \$\endgroup\$

Brian J
– Brian J

2017-11-09 18:26:24 +00:00
Commented Nov 9, 2017 at 18:26
\$\begingroup\$ Ah oops.. It indeed fails.. Now it's only outputting the input. My bad. Shouldn't make these comments when it's evening and I'm tired from work. ;) \$\endgroup\$

Kevin Cruijssen
– Kevin Cruijssen

2017-11-09 18:41:01 +00:00
Commented Nov 9, 2017 at 18:41

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