Revisions to Find whether a number is happy or not?

Commonmark migration

edited Jun 17, 2020 at 9:04

##Scala, 145 chars

Scala, 145 chars

def d(n:Int):Int=if(n<10)n*n else d(n%10)+d(n/10) def h(n:Int):Unit=n match{ case 1=>println("happy") case 4=>println("unhappy") case x=>h(d(x))}

##Scala, 145 chars

def d(n:Int):Int=if(n<10)n*n else d(n%10)+d(n/10) def h(n:Int):Unit=n match{ case 1=>println("happy") case 4=>println("unhappy") case x=>h(d(x))}

def d(n:Int):Int=if(n<10)n*n else d(n%10)+d(n/10) def h(n:Int):Unit=n match{ case 1=>println("happy") case 4=>println("unhappy") case x=>h(d(x))}

recalc

edited Apr 27, 2011 at 12:06

##Scala, 146145 chars

def d(n:Int):Int=if(n<10)(n*n) else d(n%10)+d(n/10) def h(n:Int):Unit=n match{ case 1=>println("happy") case 4=>println("unhappy") case x=>h(d(x))}

##Scala, 146 chars

def d(n:Int):Int=if(n<10)(n*n)else d(n%10)+d(n/10) def h(n:Int):Unit=n match{ case 1=>println("happy") case 4=>println("unhappy") case x=>h(d(x))}

##Scala, 145 chars

def d(n:Int):Int=if(n<10)n*n else d(n%10)+d(n/10) def h(n:Int):Unit=n match{ case 1=>println("happy") case 4=>println("unhappy") case x=>h(d(x))}

answered Apr 27, 2011 at 11:33

##Scala, 146 chars

def d(n:Int):Int=if(n<10)(n*n)else d(n%10)+d(n/10) def h(n:Int):Unit=n match{ case 1=>println("happy") case 4=>println("unhappy") case x=>h(d(x))}