Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.
Visit Stack Exchange
Stack Internal
Knowledge at work
Bring the best of human thought and AI automation together at your work.
Explore Stack Internal
from itertools import groupby s=`len(' ')` for x in' ': print s s=''.join(i+`len(list(j))` for i,j in groupby(s)) and a version without the hacky strings
from math import * from itertools import groupby s=`int(log(e))` for x in s*int(e**pi-e): print s s=''.join(i+`len(list(j))` for i,j in groupby(s)) note that e**pi-pi is very close to 20 (19.99909997918947) but slightly smaller, so it's no good to use int with
from itertools import groupby s=`len(' ')` for x in' ': print s s=''.join(i+`len(list(j))` for i,j in groupby(s)) and a version without the hacky strings
from math import * from itertools import groupby s=`int(log(e))` for x in s*int(e**pi-e): print s s=''.join(i+`len(list(j))` for i,j in groupby(s)) note that e**pi-pi is very close to 20 (19.99909997918947) but slightly smaller, so it's no good to use int with
from itertools import groupby s=`len(' ')` for x in' ': print s s=''.join(i+`len(list(j))` for i,j in groupby(s)) and a version without the hacky strings
from math import * from itertools import groupby s=`int(log(e))` for x in s*int(e**pi-e): print s s=''.join(i+`len(list(j))` for i,j in groupby(s)) note that e**pi-pi is very close to 20 (19.99909997918947) but slightly smaller, so it's no good to use int with
from itertools import groupby s=`len(' ')` for x in' ': print s s=''.join(i+`len(list(j))` for i,j in groupby(s)) and a version without the hacky strings
from math import * from itertools import groupby s=`int(log(e))` for x in s*int(e**pi-e): print s s=''.join(i+`len(list(j))` for i,j in groupby(s)) note that e**pi-pi is very close to 20 (19.99909997918947) but slightly smaller, so it's no good to use int with
from itertools import groupby s=`len(' ')` for x in' ': print s s=''.join(i+`len(list(j))` for i,j in groupby(s)) from itertools import groupby s=`len(' ')` for x in' ': print s s=''.join(i+`len(list(j))` for i,j in groupby(s)) and a version without the hacky strings
from math import * from itertools import groupby s=`int(log(e))` for x in s*int(e**pi-e): print s s=''.join(i+`len(list(j))` for i,j in groupby(s)) note that e**pi-pi is very close to 20 (19.99909997918947) but slightly smaller, so it's no good to use int with