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\(x,n=seq(x),`?`=Map)any(Map(\(i)all(Map(\(j)x[j]-x[i+j],?n)),?n-1))
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Outputs FALSE for truthy and NA for falsey.
FALSE
NA
\(x,n=seq(x))any(Map(\(i)all(Map(\(j)x[j]-x[i+j],n)),n-1))
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\(x,n=seq(x),`?`=Map)any(\(i)all(\(j)x[j]-x[i+j]?n)?n-1)
