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,&to apply the anagram transformation. Kudos! \$\endgroup\$*/@:<:, also 36b; I had that fragment in my original (albeit much much longer) solution which generated only the 3 transformations, eschewing the original input. Not sure if that path leads to any saved bytes in your solution, though. \$\endgroup\$*/@:<:is a nice insight. In theory it means you only have to return the 3 transforms and not the original, but I didn't see an obvious to take advantage of it -- I still needed to use the original in the calcs to get the other 3. Might be a way though. \$\endgroup\$