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\$\begingroup\$ If I loops all the way back around to i then s[I] will be a again, so while(I:=(I+1)%len(s))!=i and s[I]!=a: can just be while s[(I:=~-I%len(s))]!=a:. (I've included a golf of (I+1) -> ~-I in there.) - 152 \$\endgroup\$

Jonathan Allan
– Jonathan Allan

2025-05-01 20:20:04 +00:00
Commented May 1 at 20:20
\$\begingroup\$ ...get rid of enumerate and use tuples to allow shoving initialisation of variables into f's parameters - 145. \$\endgroup\$

Jonathan Allan
– Jonathan Allan

2025-05-01 20:24:07 +00:00
Commented May 1 at 20:24
\$\begingroup\$ return s>s[:len({*k})] (inverts results) saves two more. \$\endgroup\$

Jonathan Allan
– Jonathan Allan

2025-05-01 20:55:03 +00:00
Commented May 1 at 20:55

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