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In cases where you are using the ternary operator to chose between two numbers, you can do math operations instead:

In cases where you are using the ternary operator to chose between two numbers, and the conditional is either a boolean or number 1 or 0, you can do math operations instead:

In cases where you are using the conditional check with a boolean to chose between two numbers, you can do math equations instead:

In case you don't find savings after running it with a JS compressor, simply use the former (x?y:z).

Previously I thought method B couldn't ever beat A, however exceptions do exist:

In cases where you are using the ternary operator to chose between two numbers, you can do math operations instead:

Note2: there is an isolated case where (x) !== (x?1:0), as x must be typeof === "number" for it to work. However, in the case of (-x) it works just fine.

Note3: In case you don't find savings, simply use the former (x?y:z)

Previously I thought method B couldn't ever beat A, however exceptions do exist:

I created a github project that makes the simplification for us (jsFiddle demo)

Previously I thought method B couldn't ever beat A, however exceptions do exist:

(x?97:100) //original (-3*x+100) (3*!x+97)