Hi "Stoprtme"petStorm!", mame
How it works
Hi " int(17) "; "Stoprtme"petStorm!", " len('Stoprtme'petStorm!') "; ma " atan2( , ) "; me " exp( ) "; " exp(atan2(int(17), len('Stoprtme'petStorm!'))) ";
Cracking the code
The desired output, 2.956177636986737, is either a Double or a Double followed by a Long.
Using only the characters in "Stop, Hammer time!", there are four builtin operators that return non-integer Doubles:
mS, which is asinma, which is atan2me, which is expmt, which is tan
All of them contain an m, so we can use at most three of them. There is only one S and one a.
All of those operators need input, and ma is the only one that consumes two inputs. We have only three ways to push Longs:
"...",, which pushes the string's length (strictly less than 18).H, which pushes 17....!, which pushes the logical NOT of ....
We have no way of pushing something falsy as ..., so the last option will always push 0.
The output doesn't begin or end with 17 or 0. Since 15 decimal digits is the usual number of digits for a Double, it seemed likely that the output was a simple Double.
Assuming this, the code has to fall in one of the following categories:
<Long> <mS|me|mt>{1,3}<Long> <mS|me|mt>{x} <Long> <mS|me|mt>{y} ma <mS|me|mt>{z}.
In the latter case, x + y + z is either 1 or 2 and one of the Longs is 0 or 17.
The rest was basically brute force. After a few tries,
18 , {H \ ma me 2.956177636986737 =} =
returned 9, meaning that
H 9 ma me
produces the desired output.
All that's left is to eliminate all but 9 characters from the string. Spaces are noops and i is a noop on Longs, so "petStorm!" is one of the possible choices.
