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\$\begingroup\$ sometimes you can get away with n//1+1 instead of ceil but it does mean ceil(n)=n+1 but it should work for all non integer values \$\endgroup\$

fejfo
– fejfo

2017-12-23 20:26:26 +00:00
Commented Dec 23, 2017 at 20:26
\$\begingroup\$ round(x) is (x+.5)//1, +1 byte but the latter starts with a (, and if x is a sum consisting of a constant it can be useful. \$\endgroup\$

user202729
– user202729

2018-04-28 05:27:28 +00:00
Commented Apr 28, 2018 at 5:27
\$\begingroup\$ You can use 0--n//1. \$\endgroup\$

Lucenaposition
– Lucenaposition

2024-08-19 00:05:24 +00:00
Commented Aug 19, 2024 at 0:05

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