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  • 1
    \$\begingroup\$ Oh man, I totally expected this answer. I won't consider it as an actual answer, unless you generate the continued fraction yourself. \$\endgroup\$ Commented Jun 19, 2012 at 14:38
  • \$\begingroup\$ @beary605 Fair enough. \$\endgroup\$ Commented Jun 19, 2012 at 17:41
  • 3
    \$\begingroup\$ +1 Better yet (25 chars) ContinuedFraction@Sqrt@#& \$\endgroup\$ Commented Jun 20, 2012 at 0:55
  • \$\begingroup\$ What exactly are you counting here? Is this a program which takes input from stdin? Because the way you use it looks like it's a function body without the function definition. \$\endgroup\$ Commented Jun 20, 2012 at 13:19
  • \$\begingroup\$ @Peter Taylor Please see the amendment. \$\endgroup\$ Commented Jun 20, 2012 at 13:58