One of my colleagues proposed us a challenge: to write the shortest C/C++ program to determine if a number is even or odd.

These are the requirements:

• Get a number from keyboard, at run-time (not from command line)
• Output the string pari if the number is even
• Output the string dispari if the number is odd
• We can assume that the input is legal
• We can assume that the machine has a i386 architecture
• Code preprocessing is not allowed (e.g.: use #defines)

This is the best attempt we had so far (file test.c, 50B):

main(i){scanf("%d",&i);puts("dispari"+3*(~i&1));} 

Do you think we can go further?

_{(*): "dispari" is the italian for odd and "pari" is the italian for even}

One of my colleagues proposed us a challenge: to write the shortest C/C++ program to determine if a number is even or odd.

These are the requirements:

• Get a number from keyboard, at run-time (not from command line)
• Output the string pari if the number is even
• Output the string dispari if the number is odd
• We can assume that the input is legal
• We can assume that the machine has a i386 architecture
• Code preprocessing is not allowed (e.g.: use #defines)
• [edit after comments] The code can be considered valid if it compiles with gcc 4.x

This is the best attempt we had so far (file test.c, 50B):

main(i){scanf("%d",&i);puts("dispari"+3*(~i&1));} 

Do you think we can go further?

_{(*): "dispari" is the italian for odd and "pari" is the italian for even}