Revisions to Draw an asterisk triangle

added 143 characters in body

edited Oct 31, 2016 at 14:10

3.5k
11
16

#C, 47 46 45 43 bytes

Takes input from the command line

f(n){for(n&&f(n-1);~n;putchar(n--?42:10));}

Basically if n is not 0 recurse on n-1. at the top of the recursion where n is 0 it just prints a newline, the for loop terminates when n is -1 or ~n is zero, otherwise it prints ASCII 42 which is '*'. Try it on [ideone][1]

#C++ 58 Bytes + 19 for including iostream is 77

#include<iostream> int f(int n){for(n&&f(n-1);~n;std::cout<<(n--?"*":"\n"));}

main(c,v)char**v; { f(atoi(v[1])); }

a.exe 3 * ** ***

#C, 47 46 45 43 bytes

Takes input from the command line

f(n){for(n&&f(n-1);~n;putchar(n--?42:10));}

Basically if n is not 0 recurse on n-1. at the top of the recursion where n is 0 it just prints a newline, the for loop terminates when n is -1 or ~n is zero, otherwise it prints ASCII 42 which is '*'. Try it on [ideone][1]

main(c,v)char**v; { f(atoi(v[1])); }

a.exe 3 * ** ***

#C, 47 46 45 43 bytes

Takes input from the command line

f(n){for(n&&f(n-1);~n;putchar(n--?42:10));}

Basically if n is not 0 recurse on n-1. at the top of the recursion where n is 0 it just prints a newline, the for loop terminates when n is -1 or ~n is zero, otherwise it prints ASCII 42 which is '*'. Try it on [ideone][1]

#C++ 58 Bytes + 19 for including iostream is 77

#include<iostream> int f(int n){for(n&&f(n-1);~n;std::cout<<(n--?"*":"\n"));}

main(c,v)char**v; { f(atoi(v[1])); }

a.exe 3 * ** ***

added 58 characters in body

Source Link

edited Oct 14, 2016 at 18:00

cleblanc

3.5k
11
16

#C, 47 46 45 43 bytes

Takes input from the command line

f(n){for(n&&f(n-1);~n;putchar(n--?42:10));}

Basically if n is not 0 recurse on n-1. at the top of the recursion where n is 0 it just prints a newline, the for loop terminates when n is -1 or ~n is zero, otherwise it prints ASCII 42 which is '*'. Try it on [ideone][1]

main(c,v)char**v; { f(atoi(v[1])); }

a.exe 3 * ** ***

#C, 47 46 45 43 bytes

Takes input from the command line

f(n){for(n&&f(n-1);~n;putchar(n--?42:10));}

Basically if n is not 0 recurse on n-1. at the top of the recursion where n is 0 it just prints a newline, the for loop terminates when n is -1 or ~n is zero, otherwise it prints ASCII 42 which is '*'.

main(c,v)char**v; { f(atoi(v[1])); }

a.exe 3 * ** ***

#C, 47 46 45 43 bytes

Takes input from the command line

f(n){for(n&&f(n-1);~n;putchar(n--?42:10));}

Basically if n is not 0 recurse on n-1. at the top of the recursion where n is 0 it just prints a newline, the for loop terminates when n is -1 or ~n is zero, otherwise it prints ASCII 42 which is '*'. Try it on [ideone][1]

main(c,v)char**v; { f(atoi(v[1])); }

a.exe 3 * ** ***

added 212 characters in body

Source Link

edited Oct 14, 2016 at 13:39

cleblanc

3.5k
11
16

#C, 47 46 45 43 bytes

Takes input from the command line

f(n){for(n&&f(n-1);~n;putchar(n--?42:10));}

Basically if n is not 0 recurse on n-1. at the top of the recursion where n is 0 it just prints a newline, the for loop terminates when n is -1 or ~n is zero, otherwise it prints ASCII 42 which is '*'.

main(c,v)char**v; { f(atoi(v[1])); }

a.exe 3 * ** ***

#C, 47 46 45 43 bytes

Takes input from the command line

f(n){for(n&&f(n-1);~n;putchar(n--?42:10));}

main(c,v)char**v; { f(atoi(v[1])); }

a.exe 3 * ** ***

#C, 47 46 45 43 bytes

Takes input from the command line

f(n){for(n&&f(n-1);~n;putchar(n--?42:10));}

Basically if n is not 0 recurse on n-1. at the top of the recursion where n is 0 it just prints a newline, the for loop terminates when n is -1 or ~n is zero, otherwise it prints ASCII 42 which is '*'.