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String.fromCharCode(...array)is again shorter:(...a)=>String.fromCharCode(...[...Array(24)].map((_,i)=>i+(i>16)+913+32*!!a.length))\$\endgroup\$String.fromCharCodefloors, you can save another two bytes like so:(...a)=>String.fromCharCode(...[...Array(24)].map((_,i)=>i*1.06+913+32*!!a.length))\$\endgroup\$String.fromCharCode(...)but I like thati*1.06trick! Sadly comprehensions are a byte longer this time as far as I can tell. \$\endgroup\$(...a)=>String.fromCharCode(...[for(_ of Array(i=24))i++*42/41+889+32*!!a.length])(82). \$\endgroup\$!!, as there will only be zero or one args. \$\endgroup\$