Python 2, 48 bytes
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A straight forward solution. The function expects 2 points as sequences of numbers, and returns the distance between them.

 lambda a,b:sum((d-e)**2for d,e in zip(a,b))**.5

Example:

 >>> f([13.37,2,6,-7], [1.2,3.4,-5.6,7.89])
 22.50202213135522