Python 2, 47 bytes
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A straight forward solution. The function expects 2 points as sequences of numbers, and returns the distance between them.

 lambda a,b:sum((d-e)**2for d,e in zip(a,b))**.5

Example:

 >>> f([13.37, 2, 6, -7], [1.2, 3.4, -5.6, 7.89])
 22.50202213135522