Write a program that takes two integers as an input; the first can be any integer and the second is less than or equal to the number of digits in the first number. Let these numbers be `a` and `b` respectively.

The program will do the following

 - Concatenate a minimal number of `1`s to the end of `a` so the number of digits in `a` is divisible by `b`.
 - Split `a` along every `b` digits.
 - Multiply the digits in each section together.
 - Concatenate the products together (if one of the numbers is zero, then concatenate `0`).
 - Repeat this process until a number with strictly fewer than `b` digits is formed. Print this as the output, as well as the number of the process is repeated. Units are not necessary, but some form of separation between the final number and number of iterations is.

In the following test cases, the individual steps are shown for the purpose of understanding. It is not necessary for your program to display the steps.

**Test case 1**

`1883915502469, 3`

*Steps*

 1883915502469 //Iteration 1
 188391550246911
 188 391 550 246 911
 64 27 0 48 9
 64270489 //Iteration 2
 642704891
 642 704 891
 48 0 72
 48072 //Iteration 3
 480721
 480 721
 0 14
 014 //Iteration 4
 0

*Sample Output*: `0, 4`

**Test case 2**

`792624998126442, 4`

*Steps*

 792624998126442 //Iteration 1
 7926249981264421
 7926 2499 8126 4421
 756 648 96 32
 7566489632 //Iteration 2
 756648963211
 7566 4896 3211
 1260 1728 6
 126017286 //Iteration 3
 126017286111
 1260 1728 6111
 0 112 6
 01126 //Iteration 4
 01126111
 0112 6111
 0 6
 06

*Sample Output*: `06, 4`

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The program must return an error (or just not print anything) if `b>len(a)`.

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This is code golf, fellas. Standard rules apply. Shortest code in bytes wins.