Notice removed Needs detailed answers by Jamal

occurred Oct 20, 2015 at 16:11

deleted 25 characters in body

edited Oct 20, 2015 at 16:11

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I want to join strings together, but when doing this it often happens that there is a comma too muchmany, and therefore I need to remove that comma. In the belowthis code, I use the substring to delete the two last characters.

Is there aHow can this become more elegant way to solve this problem?

List<String> paramList = new ArrayList<String>( ); paramList.add( "param1" ); paramList.add( "param2" ); StringBuilder result = new StringBuilder(); for ( String p : paramList ) { result.append( p ).append( ", " ); } String withoutLastComma = result.substring( 0, result.length( ) - ", ".length( ) ); System.err.println( withoutLastComma );

I want to join strings together, but when doing this it often happens that there is a comma too much, and therefore I need to remove that comma. In the below code I use the substring to delete the two last characters.

Is there a more elegant way to solve this problem?

List<String> paramList = new ArrayList<String>( ); paramList.add( "param1" ); paramList.add( "param2" ); StringBuilder result = new StringBuilder(); for ( String p : paramList ) { result.append( p ).append( ", " ); } String withoutLastComma = result.substring( 0, result.length( ) - ", ".length( ) ); System.err.println( withoutLastComma );

I want to join strings together, but when doing this it often happens that there is a comma too many, and therefore I need to remove that comma. In this code, I use the substring to delete the two last characters.

How can this become more elegant?

List<String> paramList = new ArrayList<String>( ); paramList.add( "param1" ); paramList.add( "param2" ); StringBuilder result = new StringBuilder(); for ( String p : paramList ) { result.append( p ).append( ", " ); } String withoutLastComma = result.substring( 0, result.length( ) - ", ".length( ) ); System.err.println( withoutLastComma );

provided more pure-english description, had to change the title because of "Problem" not being allowed

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edited Oct 20, 2015 at 15:58

Simon Forsberg

59.8k
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Remove-Last-Comma-Problem Last Comma

I want to join strings together, but when doing this it often happens that there is a comma too much, and therefore I need to remove that comma. In the below code I use the substring to delete the two last characters.

Is there a more elegant way to solve this problem?

List<String> paramList = new ArrayList<String>( ); paramList.add( "param1" ); paramList.add( "param2" ); StringBuilder result = new StringBuilder(); for ( String p : paramList ) { result.append( p ).append( ", " ); } String withoutLastComma = result.substring( 0, result.length( ) - ", ".length( ) ); System.err.println( withoutLastComma );

Remove-Last-Comma-Problem

is there a more elegant way to solve this problem?

List<String> paramList = new ArrayList<String>( ); paramList.add( "param1" ); paramList.add( "param2" ); StringBuilder result = new StringBuilder(); for ( String p : paramList ) { result.append( p ).append( ", " ); } String withoutLastComma = result.substring( 0, result.length( ) - ", ".length( ) ); System.err.println( withoutLastComma );

Remove Last Comma

I want to join strings together, but when doing this it often happens that there is a comma too much, and therefore I need to remove that comma. In the below code I use the substring to delete the two last characters.

Is there a more elegant way to solve this problem?

List<String> paramList = new ArrayList<String>( ); paramList.add( "param1" ); paramList.add( "param2" ); StringBuilder result = new StringBuilder(); for ( String p : paramList ) { result.append( p ).append( ", " ); } String withoutLastComma = result.substring( 0, result.length( ) - ", ".length( ) ); System.err.println( withoutLastComma );

Notice added Needs detailed answers by 200_success

occurred Aug 2, 2015 at 19:05

Notice removed Needs detailed answers by Jamal

occurred Jul 23, 2015 at 0:59

Question Protected by Jamal

occurred Apr 6, 2015 at 12:38

Notice added Needs detailed answers by Jamal

occurred Jul 31, 2014 at 3:21

removed : Thanks a lot. - unnecessary

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edit approved Oct 27, 2011 at 14:18

Prince John Wesley

241
1
8

is there a more elegant way to solve this problem?

List<String> paramList = new ArrayList<String>( ); paramList.add( "param1" ); paramList.add( "param2" ); StringBuilder result = new StringBuilder(); for ( String p : paramList ) { result.append( p ).append( ", " ); } String withoutLastComma = result.substring( 0, result.length( ) - ", ".length( ) ); System.err.println( withoutLastComma );

Thanks a lot.

is there a more elegant way to solve this problem?

List<String> paramList = new ArrayList<String>( ); paramList.add( "param1" ); paramList.add( "param2" ); StringBuilder result = new StringBuilder(); for ( String p : paramList ) { result.append( p ).append( ", " ); } String withoutLastComma = result.substring( 0, result.length( ) - ", ".length( ) ); System.err.println( withoutLastComma );

Thanks a lot.

is there a more elegant way to solve this problem?

List<String> paramList = new ArrayList<String>( ); paramList.add( "param1" ); paramList.add( "param2" ); StringBuilder result = new StringBuilder(); for ( String p : paramList ) { result.append( p ).append( ", " ); } String withoutLastComma = result.substring( 0, result.length( ) - ", ".length( ) ); System.err.println( withoutLastComma );