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Apr 13, 2017 at 12:48 history edited CommunityBot
replaced http://crypto.stackexchange.com/ with https://crypto.stackexchange.com/
Feb 20, 2014 at 14:54 history edited Ilmari Karonen
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Feb 15, 2014 at 13:35 history tweeted twitter.com/#!/StackCrypto/status/434682349721485312
Feb 13, 2014 at 15:13 vote accept Kartik
Feb 12, 2014 at 7:54 answer added Kartik timeline score: 6
Feb 11, 2014 at 19:03 answer added tylo timeline score: 4
Feb 11, 2014 at 13:20 comment added Kartik @CodesInChaos See the example. You don't need to change the constant.
Feb 11, 2014 at 13:17 history edited Kartik CC BY-SA 3.0
added exxample
Feb 11, 2014 at 12:49 comment added CodesInChaos You can't hardcode it if you want to support all possible values of $x,z$. Garbage values of $z$ won't match the fixed $c$.
Feb 11, 2014 at 12:36 answer added fgrieu timeline score: 7
Feb 11, 2014 at 12:13 review First posts
Feb 11, 2014 at 12:52
Feb 11, 2014 at 12:11 comment added Kartik @CodesInChaos But $c$ can be hard coded in $T(x,c)$ and we can convert it to $T(x)$ again.
Feb 11, 2014 at 12:08 comment added CodesInChaos I guess the new function has to be denoted as $T(x, c) = (y, z)$ where $c$ is a constant. So $T^{-1}$ will give you a $x,c$ pair, but with an invalid $c$.
Feb 11, 2014 at 12:07 comment added Kartik @CodesInChaos Sorry, I couldn't understand that. Could you please provide an example?
Feb 11, 2014 at 12:06 comment added CodesInChaos I think you need additional inputs with fixed value when rewriting the circuit using toffoli's. When you reverse the circuit you don't get back those fixed values.
Feb 11, 2014 at 11:54 history asked Kartik CC BY-SA 3.0