Timeline for Print Link field in View template
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 3, 2015 at 22:45 | history | edited | Shawn Conn | CC BY-SA 3.0 | formatting |
| Apr 30, 2015 at 13:47 | answer | added | srodrig | timeline score: 0 | |
| Apr 30, 2015 at 0:01 | answer | added | Geoff | timeline score: 1 | |
| Apr 29, 2015 at 21:53 | comment | added | Geoff | if you're using the Link module, you can choose how the link is displayed, including plain text | |
| Apr 29, 2015 at 20:38 | history | edited | srodrig | CC BY-SA 3.0 | added 136 characters in body |
| Apr 29, 2015 at 20:35 | comment | added | srodrig | The view is displaying fields. I got the raw data from using dsm($fields). The raw data doesn't show the Link url entered by the user, it shows the node id where the Link was entered. Is this suppose to be the case or is something broken? Is there another way to display the plain text entered by the user without any HTML, other than using raw value? | |
| Apr 29, 2015 at 19:48 | comment | added | RoloDMonkey | Having said that, what is the view displaying content or fields? If you are displaying fields, then there should be a way to get the raw value in the field-level configuration of the view. | |
| Apr 29, 2015 at 19:46 | comment | added | RoloDMonkey | Even before you solve your problem, please understand that outputting raw content that is put in by users is never a good idea. You are setting yourself up for CSRF and XSS security breaches. If you are doing this in a template file, you really need to make sure that the raw content is handled by Drupal's built-in filtering functions. | |
| Apr 29, 2015 at 19:37 | history | asked | srodrig | CC BY-SA 3.0 |