Timeline for Cannot understand the attenuation in signal as the audio bit depth of adc changes
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 14, 2015 at 17:07 | vote | accept | charansai | ||
| Nov 14, 2015 at 16:55 | comment | added | charansai | @OlliNiemitalo No no, I created wav file using LabVIEW not PC ! | |
| Nov 14, 2015 at 15:54 | comment | added | Olli Niemitalo | I mean the WAV file you played with the PC's built-in sound device. | |
| Nov 14, 2015 at 15:18 | comment | added | charansai | @OlliNiemitalo Its not clearly given in the VI description, whether amplitude of 1 means volts or sth. But I think it means 1 Volt signal | |
| Nov 13, 2015 at 21:00 | comment | added | Olli Niemitalo | By amplitude of 1 in a 16-bit WAV file, do you mean that the sine wave goes from +32678 to -32767 peak-to-peak? If so, then amplitude 2.5 makes no sense as the those were already the minimum and maximum 16-bit values. | |
| Nov 13, 2015 at 20:57 | answer | added | Olli Niemitalo | timeline score: 0 | |
| Nov 13, 2015 at 7:14 | comment | added | hotpaw2 | Unless you have a complete path with a specified calibration, it's normal for signals to be attenuated or amplified by almost arbitrary values to keep typical signals within a reasonable range. To do so, the bits dropped in reduced ranges are typically the LSBs, not the most significant. | |
| Nov 13, 2015 at 1:50 | history | asked | charansai | CC BY-SA 3.0 |