Timeline for IQ FM Demodulation of Wow and Flutter Signal in Software
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 23, 2017 at 6:33 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Apr 23, 2017 at 5:44 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Mar 24, 2017 at 3:37 | answer | added | hotpaw2 | timeline score: 2 | |
| Mar 24, 2017 at 0:26 | comment | added | Dan Boschen | No it applies to analog FM as well- what are you using to process your data? (MATLAB, or?) . Did my additional info in the answer section help? | |
| Mar 24, 2017 at 0:05 | comment | added | Josef de Joanelli | @DanBoschen Those answers are sort of helpful, but I'm confused about the frequency discriminator, which I'm guessing only pertains to discrete data because it is a keying modulation. My 200Hz signal is a continuous signal that I'm trying to extract. | |
| Mar 23, 2017 at 23:57 | answer | added | Dan Boschen | timeline score: 1 | |
| Mar 23, 2017 at 23:35 | comment | added | Dan Boschen | Do our answers that we gave here help you? electronics.stackexchange.com/questions/293706/… | |
| Mar 23, 2017 at 22:51 | comment | added | Josef de Joanelli | @MarcusMüller The 200Hz signal is the frequency variations due to device imperfection. I'm trying to measure the frequency deviation and associated energy levels. | |
| Mar 23, 2017 at 22:39 | comment | added | Marcus Müller | You can't extract the input 200 Hz signal if the frequency variations due to device imperfections happen to fall into the same bandwidth. There's simply mathematically no difference between FM modulation and changing the frequency of a tone. | |
| Mar 23, 2017 at 22:38 | comment | added | Marcus Müller | In an ideal world, an FFT on the data contained in the .wav file would result in a single sharp peak at 3.15kHz: Only if your DFT length and sampling rate happen to divide such that there is a bin at exactly that frequency. WLOG, there isn't, and with limited clock accuracy and sample depth and computational precision in the real world, there actually can't be. | |
| Mar 23, 2017 at 22:38 | review | First posts | |||
| Mar 24, 2017 at 1:13 | |||||
| Mar 23, 2017 at 22:36 | history | asked | Josef de Joanelli | CC BY-SA 3.0 |