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Peter K.
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So if I understand right, $x$ is the phase function thus a signal fas the form of $f(x) = sin(x)$$f(x) = \sin(x)$ which x is the phase function and can be whatever and $f(x)$ is the amplitude function.

So if I understand right, $x$ is the phase function thus a signal fas the form of $f(x) = sin(x)$ which x is the phase function and can be whatever and $f(x)$ is the amplitude function.

So if I understand right, $x$ is the phase function thus a signal fas the form of $f(x) = \sin(x)$ which x is the phase function and can be whatever and $f(x)$ is the amplitude function.

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lennon310
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So if I understand right, x$x$ is the phase function thus a signal fas the form of f(x) = sin(x)$f(x) = sin(x)$ which x is the phase function and can be wateverwhatever and f(x)$f(x)$ is the amplitude funcitonfunction.

So if I understand right, x is the phase function thus a signal fas the form of f(x) = sin(x) which x is the phase function and can be watever and f(x) is the amplitude funciton.

So if I understand right, $x$ is the phase function thus a signal fas the form of $f(x) = sin(x)$ which x is the phase function and can be whatever and $f(x)$ is the amplitude function.

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makala
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So if I understand right, x is the phase function thus a signal fas the form of f(x) = sin(x) which x is the phase function and can be watever and f(x) is the amplitude funciton.