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jonk
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jonk
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The rest of the circuit is all resistive and fast. So it can be mentally lumped in mind as instantaneous. (Ignore any delays.)

Also, the schematic you have really will need (if you build one) a small capacitance (maybe \$22\:\text{pF}\$?) across the feedback resistor of the differentially-arranged 1st stage opamp. It's common practice, though. Just FYI.

The rest of the circuit is all resistive and fast. So it can be mentally lumped in mind as instantaneous. (Ignore any delays.)

Also, the schematic you have really will need (if you build one) a small capacitance (maybe \$22\:\text{pF}\$?) across the feedback resistor of the differentially-arranged 1st stage opamp. It's common practice, though. Just FYI.

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jonk
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The following is how I mentally visualized what I just wrote, earlier, in the Overview. I tried to use words there, but here's the mental picture that was in my mind while I was writing it:

enter image description here

For larger values of \$\omega\$ the reactance of the capacitor has a smaller value and therefore the radius of the above circle is similarly tighter/smaller, and the magnitide is therefore smaller. The differentially-arranged opamp is pushing on \$R\$, which causes the rotation. But no matter how hard it tries, \$R\$ is always positioned to be tangent to the \$C\$-axis, so all the pushing does is to just continue the rotation.

I admit that the \$R\$ and \$C\$ on your schematic was nicely arranged for me to see this circle superimposed on it when I was first reading it. I actually super-imposed the circle, mentally, then. ;)

Added

The following is how I mentally visualized what I just wrote, earlier, in the Overview. I tried to use words there, but here's the mental picture that was in my mind while I was writing it:

enter image description here

For larger values of \$\omega\$ the reactance of the capacitor has a smaller value and therefore the radius of the above circle is similarly tighter/smaller, and the magnitide is therefore smaller. The differentially-arranged opamp is pushing on \$R\$, which causes the rotation. But no matter how hard it tries, \$R\$ is always positioned to be tangent to the \$C\$-axis, so all the pushing does is to just continue the rotation.

I admit that the \$R\$ and \$C\$ on your schematic was nicely arranged for me to see this circle superimposed on it when I was first reading it. I actually super-imposed the circle, mentally, then. ;)

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jonk
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