Timeline for Given a matrix A, how to find B such that AB=BA [duplicate]
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 30, 2015 at 8:50 | history | closed | user1551 linear-algebra Users with the linear-algebra badge or a synonym can single-handedly close linear-algebra questions as duplicates and reopen them as needed. | Duplicate of Given a matrix, is there always another matrix which commutes with it? | |
| Jul 18, 2012 at 16:27 | answer | added | chaohuang | timeline score: 3 | |
| Jul 18, 2012 at 15:58 | vote | accept | ryang | ||
| Jul 18, 2012 at 6:24 | answer | added | Holdsworth88 | timeline score: 8 | |
| Jul 18, 2012 at 6:11 | comment | added | Ragib Zaman | The diagonal hint may be misleading, any diagonal matrix satisfying the requirements is necessarily a multiple of the identity matrix. | |
| Jul 18, 2012 at 6:10 | comment | added | sdcvvc | possible duplicates: math.stackexchange.com/questions/92480, math.stackexchange.com/questions/170241 | |
| Jul 18, 2012 at 6:03 | answer | added | A.S | timeline score: 5 | |
| Jul 18, 2012 at 5:54 | comment | added | ryang | Hehe, thanks. I was rather trying to construct B using the hint in the middle paragraph and had missed the obvious answers. | |
| Jul 18, 2012 at 5:54 | comment | added | Cocopuffs | $B = A$ or $B = A^2$, etc., will also work. More generally you want to find $B$ which is simultaneously diagonalizable with $A$. | |
| Jul 18, 2012 at 5:50 | comment | added | Alex Becker | What's wrong with $2I$? | |
| Jul 18, 2012 at 5:49 | history | asked | ryang | CC BY-SA 3.0 |