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Nov 14, 2014 at 12:13 comment added Greg Graviton @JakobH Note that the integration variable $t$ has a minus sign, $f(x-t)$.
Nov 13, 2014 at 11:30 comment added jak I'm certainly missing something obvious but don't we have: $\int_0^x f'(x-t) \,dt= f(x-t) \Big |_0^x=f(x-x)-f(x-0)=f(0)-f(x)$, which is wrong by a minus sign?
Feb 23, 2012 at 17:00 comment added Pedro The error term in integral form is just badass.
S Feb 4, 2011 at 16:32 history answered Greg Graviton CC BY-SA 2.5
S Feb 4, 2011 at 16:32 history made wiki Post Made Community Wiki