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Evaluating Reducing this principal value integral (or reducing it to a non-principal form)something I can evaluate numerically

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I have the following principal value integral: $$\mathcal{P}\int_0^\infty\frac{x^4}{\left(1+\frac{x^2}{B^2}\right)^{4}\sqrt{C^2+x^2}\left[\sqrt{C^2+a^2}-\sqrt{C^2+x^2}\right]}dx$$ where $a,B,C\in\mathbb{R}^+$, (and of course the singularity is at $x=a$). If it's analytically solvableIf it's analytically solvable (which I highly doubt), I'd like to know how to solve it. (which I highly doubt)As a commenter has pointed out, there is actually an elementary antiderivative for the indefinite integral, but the form is rather complicated so I'd like to know howrather just reduce it to solvea non-principal form and evaluate it numerically. If not, how) How can I manipulate it to equate it to an expression in terms of "ordinary" (non-principal-value) integrals?

It has been suggested by someone I know that I might be able to make use of the result: $$\mathcal{P}\int_0^\infty\frac{dx}{C^2-x^2}=0$$ for $C\in\mathbb{R}$, but I am unsure how to make this result useful.

I have the following principal value integral: $$\mathcal{P}\int_0^\infty\frac{x^4}{\left(1+\frac{x^2}{B^2}\right)^{4}\sqrt{C^2+x^2}\left[\sqrt{C^2+a^2}-\sqrt{C^2+x^2}\right]}dx$$ where $a,B,C\in\mathbb{R}^+$, (and of course the singularity is at $x=a$). If it's analytically solvable (which I highly doubt), I'd like to know how to solve it. If not, how can I manipulate it to equate it to an expression in terms of "ordinary" (non-principal-value) integrals?

It has been suggested by someone I know that I might be able to make use of the result: $$\mathcal{P}\int_0^\infty\frac{dx}{C^2-x^2}=0$$ for $C\in\mathbb{R}$, but I am unsure how to make this result useful.

I have the following principal value integral: $$\mathcal{P}\int_0^\infty\frac{x^4}{\left(1+\frac{x^2}{B^2}\right)^{4}\sqrt{C^2+x^2}\left[\sqrt{C^2+a^2}-\sqrt{C^2+x^2}\right]}dx$$ where $a,B,C\in\mathbb{R}^+$, (and of course the singularity is at $x=a$). If it's analytically solvable (which I highly doubt), I'd like to know how to solve it. (As a commenter has pointed out, there is actually an elementary antiderivative for the indefinite integral, but the form is rather complicated so I'd rather just reduce it to a non-principal form and evaluate it numerically.) How can I manipulate it to equate it to an expression in terms of "ordinary" (non-principal-value) integrals?

It has been suggested by someone I know that I might be able to make use of the result: $$\mathcal{P}\int_0^\infty\frac{dx}{C^2-x^2}=0$$ for $C\in\mathbb{R}$, but I am unsure how to make this result useful.

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user502382
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I have the following principal value integral: $$\mathcal{P}\int_0^\infty\frac{x^4}{\left(1+\frac{x^2}{B^2}\right)^{4}\sqrt{C^2+x^2}\left[\sqrt{C^2+a^2}-\sqrt{C^2+x^2}\right]}dx$$ where $a,B,C\in\mathbb{R}^+$, (and of course the singularity is at $x=a$). If it's analytically solvable (which I highly doubt), I'd like to know how to solve it. If not, how can I manipulate it to equate it to an expression in terms of "ordinary" (non-principal-value) integrals?

It has been suggested by someone I know that I might be able to make use of the result: $$\mathcal{P}\int_0^\infty\frac{dx}{C^2-x^2}=0$$ for $C\in\mathbb{R}$, but I am unsure how to make this result useful.

I have the following principal value integral: $$\mathcal{P}\int_0^\infty\frac{x^4}{\left(1+\frac{x^2}{B^2}\right)^{4}\sqrt{C^2+x^2}\left[\sqrt{C^2+a^2}-\sqrt{C^2+x^2}\right]}dx$$ where $a,B,C\in\mathbb{R}^+$, (and of course the singularity is at $x=a$). If it's analytically solvable (which I highly doubt), I'd like to know how to solve it. If not, how can I manipulate it to equate it to an expression in terms of "ordinary" (non-principal-value) integrals?

I have the following principal value integral: $$\mathcal{P}\int_0^\infty\frac{x^4}{\left(1+\frac{x^2}{B^2}\right)^{4}\sqrt{C^2+x^2}\left[\sqrt{C^2+a^2}-\sqrt{C^2+x^2}\right]}dx$$ where $a,B,C\in\mathbb{R}^+$, (and of course the singularity is at $x=a$). If it's analytically solvable (which I highly doubt), I'd like to know how to solve it. If not, how can I manipulate it to equate it to an expression in terms of "ordinary" (non-principal-value) integrals?

It has been suggested by someone I know that I might be able to make use of the result: $$\mathcal{P}\int_0^\infty\frac{dx}{C^2-x^2}=0$$ for $C\in\mathbb{R}$, but I am unsure how to make this result useful.

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