Timeline for Differentiation using first principles with rational powers
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 13, 2017 at 12:19 | history | edited | CommunityBot | replaced http://math.stackexchange.com/ with https://math.stackexchange.com/ | |
| May 6, 2013 at 21:50 | answer | added | Dave L. Renfro | timeline score: 8 | |
| May 6, 2013 at 2:32 | vote | accept | Samuel Tan | ||
| May 6, 2013 at 1:56 | comment | added | Julian Rosen | In general, for $(ax+b)^{1/n}$, you can multiply numerator and denominator by $\displaystyle \sum_{j=0}^{n-1} (a(x+h)+b)^{\frac{j}{n}}(ax+b)^{\frac{n-1-j}{n}}$. After multiplying out, the numerator will just be $ah$. | |
| May 6, 2013 at 1:51 | comment | added | Samuel Tan | How would this work for $(ax+b)^{1/3}$? | |
| May 6, 2013 at 1:50 | answer | added | user17762 | timeline score: 4 | |
| May 6, 2013 at 1:50 | comment | added | Samuel Tan | Right...why didn't I see that before..duh! Thank you! | |
| May 6, 2013 at 1:48 | comment | added | Julian Rosen | Hint: Multiple the numerator and denominator by $\sqrt{a(x+h)+b}+\sqrt{ax+b}$. | |
| May 6, 2013 at 1:47 | history | asked | Samuel Tan | CC BY-SA 3.0 |