Linked Questions
13 questions linked to/from Recursive Integration over Piecewise Polynomials: Closed form?
32 votes
10 answers
4k views
Formula for bump function
I would like to formulate a bump function (link) $f:\Bbb R \to\Bbb R$ with the following properties on the reals: $$ f(x) = \begin{cases} 0, & \mbox{if } x \le -1 \\ 1, & \mbox{if } x = 0 \\...
89 votes
1 answer
3k views
Conjectured formula for the Fabius function
The Fabius function is the unique function ${\bf F}:\mathbb R\to[-1, 1]$ satisfying the following conditions: a functional–integral equation$\require{action} \require{enclose}{^{\texttip{\dagger}{a ...
8 votes
5 answers
1k views
Are there smooth analogs to polynomial splines
Is possible to construct infinitely differentiable functions that interpolate through arbitrary points, the way polynomial splines do? If so, do they have a name and is there an algorithm for ...
12 votes
3 answers
688 views
Evaluating $f(x) f(x/2) f(x/4) f(x/8) \cdots$
Let $f : \mathbb R \to \mathbb R$ be a given function with $\lvert f(x) \rvert \le 1$ and $f(0) = 1$. Is there a nice simplified expression for $$\begin{align}F(x) &= f(x) f(x/2) f(x/4) f(x/8) \...
14 votes
2 answers
1k views
How to compute the values of this function ? ( Fabius function )
How to compute the values of this function ? ( Fabius function ) It is said not to be analytic but $C^\infty$ everywhere. But I do not even know how to compute its values. Im confused. Here is the ...
15 votes
2 answers
627 views
Extracting an asymptotic from a sequence defined by a recurrence relation
Suppose I have a sequence defined via its first term and a recurrence relation involving summation over all previous values with some coefficients. Here is the sequence I am interested in right now (...
7 votes
2 answers
1k views
Infinite product of sinc functions
Calculate the infinite product $f_q(x):=\prod_{n=0}^\infty\frac{\sin(q^n x)}{q^n x}$, where $x$ is real and $0<q<1$. In other words, $f_q$ must satisfy the functional equation $f_q(x)=f_q(qx)\...
7 votes
1 answer
485 views
Extrema of an infinite product of sinc functions
Consider the function $$f(x)=\prod_{n=0}^\infty\operatorname{sinc}\left(\frac{\pi \, x}{2^n}\right),\tag1$$ where $\operatorname{sinc}(z)$ denotes the sinc function. It arises as a Fourier transform ...
15 votes
1 answer
473 views
An elementary function with asymptotic $f'(x)\sim2f(2x)$ for $x\to0^+$
We want to find an elementary function $f(x)$ that is smooth and strictly increasing on some interval $x\in(0,\epsilon)$, satisfying $\lim\limits_{\,x\to0^+}f(x)=0$, whose asymptotic for $x\to0^+$ is $...
9 votes
1 answer
550 views
Calculating the Fabius function.
Yesterday I learned about the strange Fabius function $f$ in this question. Given my interest in neural networks and the fact that this function has a distinct sigmoid shape, I became curious about ...
5 votes
0 answers
222 views
Solution of advanced functional differential equation
Statement Consider an advanced functional differential equation $$ Lf(x) = f(2x+\pi)+f(2x-\pi),\quad L\equiv\frac{d^2}{dx^2}+1. \tag{1} $$ Let's construct a solution of Eq. $(1)$ with finite ...
0 votes
2 answers
151 views
On the solution to $u'(x)=2u(2x+1)-2u(2x-1)$ and the Fabius function
Looking for closed-form examples of Delay Differential Equations I found that $$u'(x)=2u(2x+1)-2u(2x-1)$$ could had as solution a modification of the Fabius function $F(x)$, which "is an example ...
3 votes
0 answers
152 views
Finding the close form of an Integral (smooth bump function)
I am trying to build a function $q(x)$ from another function $f(x)$ as: $g(x)=f(x+1)-f(x-1)$ $z(x)=\int\limits_{-2}^{x} g(u)\ du$ $q(x)=z(2x)$ from the function I took from here: $$f(x) = \begin{...