Linked Questions
37 questions linked to/from Proof of upper-tail inequality for standard normal distribution
7 votes
1 answer
13k views
bounds on normal distribution [duplicate]
Possible Duplicate: Proof of upper-tail inequality for standard normal distribution Proof that $x \Phi(x) + \Phi'(x) \geq 0$ $\forall x$, where $\Phi$ is the normal CDF Let $X$ be a normal $N(0,...
6 votes
1 answer
1k views
Prove $\int_t^{\infty} e^{-x^2/2}\,dx > e^{-t^2/2}\left(\frac{1}{t} - \frac{1}{t^3}\right)$ [duplicate]
How to formally prove the following inequality - $$\int_t^{\infty} e^{-x^2/2}\,dx > e^{-t^2/2}\left(\frac{1}{t} - \frac{1}{t^3}\right)$$
2 votes
2 answers
613 views
Integral with inequality: $\int_a^\infty e^{-x^{2}}dx≤ \frac 1{2a}e^{-a^{2}} $ [duplicate]
By comparison with the integral of $ \frac xae^{-x^{2}}$ Show that $\int_a^\infty e^{-x^{2}}dx≤ \frac 1{2a}e^{-a^{2}} $ Given that $a>0$.
1 vote
1 answer
551 views
Show that $\frac{1}{x}-\frac{1}{x^3}<\frac{P(X>x)}{\phi(x)}<\frac{1}{x}$ for $x>0$ where $X$~$N(0,1)$ with pdf $\phi(x)$. [duplicate]
I tried taking exponentials and using Markov's Inequality, but this only gave me an upper bound of $\sqrt{2\pi}$. I'm not sure how to begin to approach this question - can anyone give a hint?
2 votes
1 answer
242 views
Double inequality involving gaussian and erf functions [duplicate]
I want to establish the following inequality for $x>0$: $$\phi(x) \left( \frac{1}{x} - \frac{1}{x^3}\right)\leq 1- \Phi(x) \leq \phi(x) \frac{1}{x}$$ with $\phi(x)=\frac{1}{\sqrt{2 \pi}}e^{-\frac{...
1 vote
1 answer
246 views
limiting behavior of standard normal survivor function [duplicate]
How do you show that $\lim_{x\to \infty} 1-\Phi(x) \sim \phi(x)/x$? In the previous, I'm using $\Phi$ to refer to the standard normal CDF and $\phi$ to refer to the standard normal pdf. Thanks!!
16 votes
5 answers
4k views
Proof that $x \Phi(x) + \Phi'(x) \geq 0$ $\forall x$, where $\Phi$ is the normal CDF
As title. Can anyone supply a simple proof that $$x \Phi(x) + \Phi'(x) \geq 0 \quad \forall x\in\mathbb{R}$$ where $\Phi$ is the standard normal CDF, i.e. $$\Phi(x) = \int_{-\infty}^x \frac{1}{\...
11 votes
2 answers
7k views
Proof of an estimate for the tail of a normal distribution
My advisor told me to look up the proof of the following standard estimate so that we can adapt it to the case where we are dealing with something similar but including the addition of a polynomial ...
15 votes
4 answers
788 views
Selecting a menu
While perusing old unanswered puzzle questions, I came across this one. I found it quite interesting, but a bit vague, so I've decided to recast it. A party is to be held at a restaurant. The ...
4 votes
2 answers
4k views
Lower bound on $P(X>\lambda)$ where $X$ is Gaussian.
Suppose X is a 0 mean Gaussian random variable with variance 1. I'm trying to find a lower bound on $P(X>\lambda)$. Specifically I'd like to derive a lower bound of the form $c e^{-C\lambda^2}$ ...
5 votes
2 answers
2k views
Approximation of the binomial distribution
Let $S_n=\dfrac{B_n - np}{\sqrt{n\cdot p\cdot (1-p)}}$ be a random variable which has the standardized binomial distribution. From Chebyshev's inequality I know that $$P(|S_n| \ge x) \le \frac{1}{x^2}$...
2 votes
1 answer
2k views
Upper-tail inequality for t-distribution
I am interested in upper tail bounds (or bounds on deviation from the mean) for t-distribution with n degrees of freedom (http://en.wikipedia.org/wiki/Student's_t-distribution) A bound that is of the ...
8 votes
2 answers
194 views
Prove $\lim_{c\to\infty} P(X-\varepsilon<Y<X+\varepsilon\mid X>c,Y>c)=1$ for all $\varepsilon>0$ if $X,Y$ are i.i.d. Normal$(0,1)$?
Suppose random variables $X$ and $Y$ are i.i.d. Normal$(0,1)$. Consider the following events, where $\varepsilon>0, c>0$: $$\begin{align*} Q&=\{(x,y)\in\Bbb R^2: x>c, y>c\}\\ C&=\{(...
2 votes
2 answers
1k views
how to find area under normal distribution curve
Find out the area in percentage under standard normal distribution curve of random variable $Z$ within limits from $-3$ to $3$. my try: probability density function of standard normal distribution is ...
2 votes
1 answer
2k views
Upper bound inequality cumulative normal distribution
According to this post, I found for $X \sim N(0,1)$, $x > 0$ the result that \begin{align} \frac{1}{\sqrt{2\pi}}\big(\frac{1}{x}-\frac{1}{x^3}\big)e^{-\frac{x^2}{2}} \leq P(X>x) \leq \frac{1}{\...