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André Nicolas
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If you define a complex number as an ordered pair $(x,y)$ of real numbers, then the set of real numbers is not a subset of the set of complex numbers.

That is a problem that is easy to fix. The complex numbers of the form $(x,0)$ are a "copy" of the reals in the complex numbers. We informally identify this copy with the real reals, and then don't worry about it.

André Nicolas
  • 515.9k
  • 47
  • 589
  • 1k