Timeline for Derivatives (divergence, gradient, curl) of interpolated 3D data
Current License: CC BY-SA 3.0
16 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 7, 2012 at 13:02 | vote | accept | Eli Lansey | ||
| Sep 6, 2012 at 21:22 | answer | added | Simon Woods | timeline score: 8 | |
| Sep 6, 2012 at 20:00 | history | edited | Eli Lansey | CC BY-SA 3.0 | added 182 characters in body |
| Sep 6, 2012 at 18:12 | answer | added | Dr. belisarius | timeline score: 4 | |
| Sep 6, 2012 at 18:02 | history | tweeted | twitter.com/#!/StackMma/status/243771168337846272 | ||
| Sep 6, 2012 at 16:56 | comment | added | Eli Lansey | @belisarius Yeah. And I've never been strong with the Hold's stuff. | |
| Sep 6, 2012 at 16:17 | comment | added | Dr. belisarius | @EliLansey hehe .. me too. The eval order is driving me nuts :) | |
| Sep 6, 2012 at 16:10 | comment | added | Eli Lansey | @belisarius J.M. pointed that out in chat, but I've been having trouble getting it to work with the interpolated functions. | |
| Sep 6, 2012 at 15:24 | comment | added | Dr. belisarius | From the help D[f, {{x1, x2, ...}}] gives the vector derivative | |
| Sep 6, 2012 at 14:43 | comment | added | user21 | have you looked at Derivative for this. e.g. Derivative[0,0,1][intf][x,y,z]. (I have to go now, so I can not post a solution) | |
| Sep 6, 2012 at 14:41 | comment | added | Eli Lansey | @ruebenko yup. good catch. fixed it. | |
| Sep 6, 2012 at 14:41 | history | edited | Eli Lansey | CC BY-SA 3.0 | edited body |
| Sep 6, 2012 at 14:40 | comment | added | user21 | Is there a typo in the last component of the curl, should that be D[#[[1]], y]? | |
| Sep 6, 2012 at 14:04 | history | edited | Eli Lansey | CC BY-SA 3.0 | added 6 characters in body |
| S Sep 6, 2012 at 13:51 | answer | added | Eli Lansey | timeline score: 6 | |
| S Sep 6, 2012 at 13:51 | history | asked | Eli Lansey | CC BY-SA 3.0 |