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Jul 30, 2021 at 19:47 vote accept Dylan Solms
Aug 8, 2016 at 0:30 answer added Michael E2 timeline score: 5
Aug 7, 2016 at 13:37 history edited m_goldberg CC BY-SA 3.0
Routine clean-up
Aug 7, 2016 at 13:28 answer added Feyre timeline score: 7
Aug 7, 2016 at 13:13 comment added Dylan Solms Yes, a position dependant force.
Aug 7, 2016 at 12:59 comment added Feyre So, you are trying to solve a differential equation where a particle undergoes a position dependent force?
Aug 7, 2016 at 12:56 comment added george2079 you obviously don't want to define x before you solve for it anyway. Your equation is second order F=m x''[t], hope that helps. (I assume F is force, though you don't actually say that ). I,ll add your attempt looks like you are trying to make some use of some constant acceleration expressions. Your acceleration is most definately not constant, you cant use those.
Aug 7, 2016 at 12:08 history edited J. M.'s missing motivation
"not homework"
Aug 7, 2016 at 12:06 history edited dionys
edited tags
S Aug 7, 2016 at 12:05 history suggested mattiav27 CC BY-SA 3.0
improved formatting
Aug 7, 2016 at 12:03 comment added Dylan Solms Cool. Not homework. I have free time and am trying to learn Mathematica. Found this Physics problem but it seems a bit hard for me. Didn't realize ClearAll[x] does this. Just saw it being used...
Aug 7, 2016 at 11:53 comment added mattiav27 Also if this is an homework, you should the appropriate tag...
Aug 7, 2016 at 11:52 comment added mattiav27 So you define x[t_] := (F[x]/(2*m))*t^2 + x'[t]*t + x0 then you ClearAll[x]? This clears you definition, or am I lost?
Aug 7, 2016 at 11:50 review Suggested edits
S Aug 7, 2016 at 12:05
Aug 7, 2016 at 11:42 history edited J. M.'s missing motivation
edited tags
Aug 7, 2016 at 11:32 history asked Dylan Solms CC BY-SA 3.0