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Mar 8, 2017 at 0:48 comment added Daniel Lichtblau Somewhat more ghastly: In[255]:= sum = Sum[a[j]*x^j, {j, 1, 10}]; Apply[List, Coefficient[ Nest[Expand[sum*#] /. {a[x_]^2 :> 0, x^j_ /; j > 28 :> 0} &, sum, 3], x^28]] /. ii_Integer*(x : Repeated[a[_], {4}]) :> {x} /. a[j_] :> j Out[256]= {{5, 6, 8, 9}, {4, 7, 8, 9}, {5, 6, 7, 10}, {4, 6, 8, 10}, {3, 7, 8, 10}, {4, 5, 9, 10}, {3, 6, 9, 10}, {2, 7, 9, 10}, {1, 8, 9, 10}}
Mar 7, 2017 at 20:47 history answered Daniel Lichtblau CC BY-SA 3.0