Timeline for Mathematica won't solve: $(H-T)^x-(L+T)^x=x*c/p$
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
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| Jun 11, 2017 at 12:23 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| May 12, 2017 at 12:01 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Apr 12, 2017 at 11:45 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Mar 13, 2017 at 10:50 | answer | added | Michael E2 | timeline score: 2 | |
| Mar 13, 2017 at 10:16 | history | edited | Nofar Duani | CC BY-SA 3.0 | edited title |
| Mar 12, 2017 at 16:00 | history | edited | Nofar Duani | CC BY-SA 3.0 | edited body |
| Mar 12, 2017 at 15:58 | comment | added | Nofar Duani | I have MAtheatica 9.0. The use of the Y in the first equation was a mistake. I've changed it now in the question. Thanks for letting me know. When I run the Solve function as you suggested (but with T instead of Y) I get the error notification: Solve::nsmet: This system cannot be solved with the methods available to Solve. | |
| Mar 12, 2017 at 15:55 | comment | added | JimB | What "error messages"/output are you getting? "nothing seems to work" doesn't tell us anything. Plus for Mathematica 10.4.1 on Windows 10 Solve[((H - T)^x - (L + y)^x)/x == c/p, T] works fine for me. And your equations are not the same: T appears just once in the first equation and twice in the other two equations. | |
| Mar 12, 2017 at 15:51 | comment | added | Daniel Lichtblau | It's a transcendental equation in T (bad idea to use capital letters for variables, by the way), and not in any obvious way reducible to a form Solve might be able to handle. So i doubt there will be any general solution in terms of the unspecified parameters. For given numeric values there might be a chance, when restricted to 0<x<=1. | |
| Mar 12, 2017 at 15:43 | history | edited | Nofar Duani | CC BY-SA 3.0 | added 188 characters in body |
| Mar 12, 2017 at 15:31 | history | asked | Nofar Duani | CC BY-SA 3.0 |