Skip to main content
Mathematica

You are not logged in. Your edit will be placed in a queue until it is peer reviewed.

We welcome edits that make the post easier to understand and more valuable for readers. Because community members review edits, please try to make the post substantially better than how you found it, for example, by fixing grammar or adding additional resources and hyperlinks.

Required fields*

6
  • $\begingroup$ I found another solution, which is again not that great (as in it is super slow), but at least it gives me the results I want: Rasterize[TraditionalForm[a]]+Rasterize[TraditionalForm[b]] $\endgroup$ Commented Nov 4, 2012 at 19:18
  • $\begingroup$ What exactly are you trying to do? I see the problem but I don't understand the objective well enough to offer alternatives. Your suggested fix still makes x+1 turn into 1+x, right? $\endgroup$ Commented Nov 4, 2012 at 19:26
  • 1
    $\begingroup$ @Rojo actually, don't worry about it. I figured it out. plus = Row[{#1, " + ", #2}] &; was what I was looking for: x~plus~1 // TraditionalForm gives exactly what I want. $\endgroup$ Commented Nov 4, 2012 at 19:29
  • $\begingroup$ Yeah, that would work for 2 arguments, for more you can use Riffle. Row@Riffle[{##}, " + "] &. I would prefer using that as Format to plus more than as an ownvalue. Something like Format[plus[args__]] := Interpretation[HoldForm[Plus[args]], plus[args]] $\endgroup$ Commented Nov 4, 2012 at 19:49
  • 2
    $\begingroup$ Also, perhaps you would like wrapping your code in Module (or Block, depending on what you are doing) with Plus=plus, so you can use the + symbol at will. Module[{Plus = plus}, x + 1] $\endgroup$ Commented Nov 4, 2012 at 19:50