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  • $\begingroup$ Just a question. Is it right, that StreamPlot[{v1[x,y],v2[x,y]}] returns a set of solutions of the differential equations x'=v1; y'=v2? It looks like an elementary information that everybody knows. But it happened that I do not know, and there is no explicit discussion of this point in the Help/StreamPlot. Please let me know. Where could I have a look at the proof, or at least, an explanation? If I understand right, the StreamPlot simply yields the phase portrait, does it? $\endgroup$ Commented Nov 6, 2012 at 10:51
  • $\begingroup$ @AlexeiBoulbitch yes it yields a set of solutions for the homogenous set of equations. But it does not attempt to be continuous. In the previous example if you remove + 0.5 Cos[1.1 t] you will see that the red curve and the underlying flow become identical. $\endgroup$ Commented Nov 7, 2012 at 17:48