Timeline for How do I expand only the argument of a function?
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
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| Apr 25, 2020 at 17:18 | vote | accept | Quasar Supernova | ||
| Dec 1, 2019 at 22:01 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
| Nov 1, 2019 at 21:18 | answer | added | Carl Woll | timeline score: 3 | |
| May 22, 2017 at 17:00 | comment | added | Michael E2 | What would be the output you would expect? In particular what are the terms up to order x^3 of Exp[Sqrt[1 + x]/x] that you would expect to see? | |
| May 22, 2017 at 16:23 | comment | added | Quasar Supernova | Imagine I want to expand the exponents of each of these terms (below) up to order x^3 . (x^2 + Cos[x]) Exp[Sqrt[1 + x]/x] + | |
| May 21, 2017 at 14:08 | comment | added | Michael E2 | Then I do not understand what output you want. Please update the question with the formula you want as the output for the expansion of Exp[ Sqrt[1+x]/x ]. | |
| May 21, 2017 at 13:32 | comment | added | Quasar Supernova | Mr. Michael E2 , this will not do as I want to do this outside the argument of Exp function not inside but the effect has to be same as expanding the argument inside the argument of Exp. | |
| May 20, 2017 at 14:30 | history | edited | J. M.'s missing motivation | edited tags | |
| May 20, 2017 at 13:12 | comment | added | Michael E2 | You suggest this example is not entirely representative, so I don't know whether this will work in all your cases: Exp[Sqrt[1 + x]/x] /. Exp[u_] :> Exp[Series[u, {x, 0, 3}]] | |
| May 20, 2017 at 12:36 | history | edited | Kuba | CC BY-SA 3.0 | added 13 characters in body |
| May 20, 2017 at 12:24 | history | asked | Quasar Supernova | CC BY-SA 3.0 |