Timeline for Taking the limit of a sum
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Sep 8, 2017 at 10:00 | vote | accept | GambitSquared | ||
| Sep 7, 2017 at 21:40 | answer | added | Itai Seggev | timeline score: 3 | |
| Sep 4, 2017 at 8:31 | comment | added | LouisB | I do not know why CubeRoot works and Power[... , 1/3] does not. I try to use the Surd function for roots. See this question about n-th roots and this question about real roots for more information. | |
| Sep 4, 2017 at 7:26 | comment | added | GambitSquared | @LouisB Why does CubeRoot work?! | |
| Sep 3, 2017 at 22:43 | comment | added | LouisB | Try Limit[Sum[2/n CubeRoot[1 + (2 i - 1)/n], {i, 1, n}], n -> \[Infinity]] | |
| Sep 3, 2017 at 21:08 | comment | added | Michael E2 | You can try Needs["NumericalCalculus`"]; NLimit[Sum[..], n -> \[Infinity]] -- it gives exactly the same answer as Integrate[..] // N. | |
| Sep 3, 2017 at 21:00 | comment | added | Szabolcs | Sum and Limit are evaluated separately. In the first case Sum cannot be evaluated for arbitrary n. In the second, it can. | |
| Sep 3, 2017 at 20:56 | history | asked | GambitSquared | CC BY-SA 3.0 |