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Timeline for Taking the limit of a sum

Current License: CC BY-SA 3.0

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Sep 8, 2017 at 10:00 vote accept GambitSquared
Sep 7, 2017 at 21:40 answer added Itai Seggev timeline score: 3
Sep 4, 2017 at 8:31 comment added LouisB I do not know why CubeRoot works and Power[... , 1/3] does not. I try to use the Surd function for roots. See this question about n-th roots and this question about real roots for more information.
Sep 4, 2017 at 7:26 comment added GambitSquared @LouisB Why does CubeRoot work?!
Sep 3, 2017 at 22:43 comment added LouisB Try Limit[Sum[2/n CubeRoot[1 + (2 i - 1)/n], {i, 1, n}], n -> \[Infinity]]
Sep 3, 2017 at 21:08 comment added Michael E2 You can try Needs["NumericalCalculus`"]; NLimit[Sum[..], n -> \[Infinity]] -- it gives exactly the same answer as Integrate[..] // N.
Sep 3, 2017 at 21:00 comment added Szabolcs Sum and Limit are evaluated separately. In the first case Sum cannot be evaluated for arbitrary n. In the second, it can.
Sep 3, 2017 at 20:56 history asked GambitSquared CC BY-SA 3.0